3x^2-100x+300=0

Solution for 3x^2-100x+300=0 equation:

3x^2-100x+300=0

a = 3; b = -100; c = +300;
Δ = b2-4ac
Δ = -1002-4·3·300
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-80}{2*3}=\frac{20}{6}
=3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+80}{2*3}=\frac{180}{6}
=30
$